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Must be considered and the resulting composition is taken as the starting point
For the calculation.
The computation is performed line by line. First, it is assumed that potassium
And chlorine react completely to potassium sulfide and sodium chloride, respectively.
In this simplified model, all the potassium from the black liquor (18 kg t–1
Of black liquor solids) turns into K2S in the smelt. Using the molecular weights of
potassium (39 kg kmol–1) and sulfur (32 kg kmol–1), the sulfur bound in K2S is
then 18. 32/(2. 39) = 7 kg t–1 of black liquor solids. The remaining sulfur,
Kg, is distributed between sodium sulfide and sodium sulfate according
to the degree of reduction, DR, also termed the “reduction efficiency”:
DR _
Na2S
Na2S _ Na2SO4 _11_
Values for the chemicals in Eq. (11) can be inserted on a molar basis, equivalent
basis or sulfur weight basis, all of which give the same result. Assuming 95%
Chemical Recovery Processes
Tab. 9.3 Simplified calculation of smelt and flue gas constituents from black liquor solids.
System
input/output
Composition
[wt.%]
Smelt constituents
[kg ton–1 dry solids]
Flue gas constituents
[kg ton–1 d.s.]
Na2CO3 Na2S K2S Na2
SO4 NaCl N2 H2O CO2
O2
Black liquor solids 100%
Potassium, K 1.8% 18
Chlorine. Cl 0.5% 5
Sulphur. S 4.6% 37 7 2
Sodium. Na 19.6% 137 53 3 3
Carbon. C 35.8% 36 322
Hydrogen. H 3.6% 36
Oxygen. O 34.1% 143 4 288 859 –953
Smelt total 316 89 25 9 8
Air 100.0%
Nitrogen. N 75.6% 3.765
Oxygen. O 23.0% 1.144
Humidity 1.4% 70
Water and steam
Water in black liquor 333
Soot blowing steam 100
Flue gas total 3.765 827 1.181 191
reduction efficiency, 0.95. 39 = 37 kg sulfur are with Na2S, and the remaining
2 kg are with Na2SO4. Next comes sodium, with 37. (2. 23)/32 = 53 kg bound to
Na2S, 2. (2. 23)/32 = 3 kg in Na2SO4 and 5. 23/35.5 = 3 kg in NaCl. The
remaining sodium is converted to sodium carbonate: 196 – 53 – 3 – 3 = 137 kg.
Na2CO3 binds 137. 12/(2. 23) = 36 kg carbon. The rest of the carbon is oxidized
To CO2. Hydrogen from the black liquor is converted to water vapor. Finally, the
Oxygen demand can be calculated by summing up oxygen bound in carbonate,
sulfate, water vapor and carbon dioxide:
137. (3. 16)/(2. 23) + 2. (4. 16)/32 + 36. 16/(2. 1) + 322. (2. 16)/
Kg.
Recovery
As the black liquor solids contain just 341 kg of oxygen per ton, 953 kg must be
provided with combustion air. Assuming 20% excess air, the oxygen in air is
Kg. Nitrogen and humidity follow from the air composition. For
Calculating the total flue gas flow, we need to consider the water content of the
black liquor and the steam used for sootblowing. Supposing 75% black liquor solids,
the water coming with 1 ton of solids is 1000/0.75 – 1000 = 333 kg. The final
Total is about 450 kg of smelt and 6000 kg of wet flue gas per ton of dry liquor
Solids. The flue gas mass is equivalent to a volume of around 4800 standard cubic
Meters. Note that the above is a quite rough approach to the boiler mass balance,
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Air is sucked from the boiler house through the forced draft fan and enters the | | | As minor streams are neglected, such as dust, sulfur dioxide, reduced sulfur compounds |