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Just as we did with the mean, we can also determine the sample size for estimating the population proportion p.
We know that confidence interval for p is given by
where - is the sample proportion.
This interval is centered on the sample proportion and extends a distance L:
This result can not be used directly to determine the sample size n necessary to obtain a confidence interval of some specific width, since it involves , which is not known. But whatever the outcome, can not be bigger than 0.25, its value when the sample proportion is 0.5. Thus, the largest possible value for L is given by
Using basic algebra, we obtain
and squaring yields
Definition:
Let a random sample be selected from a normal population.
confidence interval for the population proportion, extending a distance of at most L on each side of the sample proportion, can be guaranteed if the sample size is
Example:
A public health survey is to be designed to estimate the proportion p of a population having defective vision. How many persons should be examined if the public health doctor wishes to be 98 % certain that error of estimation is below 0.05?
Solution:
The public health doctor wants the 98 % confidence interval to be
Therefore . The value of for a 98 % confidence level is 2.33.
After substituting we obtain that the required sample size is
.
Thus, if the doctor takes a sample of 543 persons, the estimate of p will be within 0.05 of the population proportion.
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Sample size determination for the estimation of mean | | | Exercises |