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Prove: AC is not perpendicular to DE
Statements | Reasons |
B is the midpoint of AC and DE | Given |
Angle 1 and angle 2 are supp | Given |
The vertical angles of 1 and 2 are also supp. | Definition of vertical angles |
AC is not perpendicular to DE | Definition of intersecting lines |
Theorem 1-2
Through a line and a point not on the line there is exactly one plane:
Given: B is non collinear to line AC
Prove: B is coplanar to AC
Statements | Reasons |
B is non collinear to AC | Given |
B is on the same plane as AC | Definition of coplanar |
B is coplanar to AC | substitution |
Theorem 1-3
If 2 lines intersect, then exactly one plane contains the lines
Given: AB and CD intersect
Prove: AB and CD are coplanar
Statements | Reasons |
AB and CD intersect | Given |
AB and CD form 2 lines | Postulate 6 |
AB and CD are coplanar | Postulate 8 |
Theorem 2-1
Known as the midpoint theorem where a midpoint of a line splits the line into 2 halves.
Given: B is collinear to AC
Prove: B is the midpoint of AC
Statements | Reasons |
B is collinear to AC | Given |
AB + BC= AC | Postulate 2 |
B is equidistant from A and C | Def. of a midpoint |
B is the midpoint of AC | substitution |
Theorem 2-2
Known as the angle bisector theorem where a bisector of an angle splits that angle into 2 halves.
Given: DB bisects angle ABC
Prove: angle ABD is congruent to angle CBD
Statements | Reasons |
DB bisects angle ABC | Given |
ABD + CBD = ABC | Postulate 4 |
ABD = CBD | Definition of angle bisector |
½ of ABC = ABD or CBD | Angle bisector theorem |
Theorem 2-3
Vertical angles are congruent
Given: line AB intersects line CD
Prove: 1 = 2
Statements | Reasons |
Line AB intersects line CD | Given |
AB and CD form opposite = angles | Def. of vertical angles |
1 and 2 are opposite angles | substitution |
1 = 2 | Theorem 2-3 |
Theorem 2-4
If 2 lines are perpendicular, then they form congruent adjacent angles
Given: AB is perpendicular to CD
Prove: 1 + 2 are both 90 degrees
Statements | Reasons |
AB is perpendicular to CD | Given |
1 = 3 | Theorem 2-3 |
1 = 2 | Def. of adjacent angles |
1 + 2 are both 90 degrees | Theorem 2-4 |
Theorem 2-5
(Converse of 2-4)
Theorem 2-6
If The exterior sides of 2 adjacent acute angles are perpendicular, then the angles are complementary.
Given: AB is perpendicular to CD
EB bisects ABC
Prove: ABE + EBC = 90
Statements | Reasons |
AB is perpendicular to CD with E bisecting them | Given |
ABE = EBC | Def. of angle bisector |
ABC = 90 degrees | Def. of perpendicular lines |
ABE + EBC = 90 | transitive |
ABE + EBC = ABC | Theorem 2-6 (substitution) |
Theorem 2-7
If two angles are supplements of congruent angles (or the same angle), then the 2 angles are congruent
Given:?
Theorem 2-8
Same as 2-7, but with complementary angles
Theorem 3-1
If 2 parallel planes are cut by a 3rd plane, then the lines of the intersection are paralell.
Theorem 3-2
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