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In previous section, we have learned that one of the conditions required to apply the binomial probability distribution is that the trials are independent so that the probabilities of the two outcomes (success and failure) remains constant. If the trials are not independent, we can not apply the binomial probability distribution to find probability of x successes in n trials. In such cases we replace the binomial distribution by the hypergeometric probability distribution. Such a case occurs when a sample is drawn without replacement from a finite population.
Definition:
Let
total number of elements in the population
number of successes in the population
number of failures in the population
number of trials (sample size)
number of successes in n trials
number of failures in n trials.
The probability of x successes in n trials is given by
Example:
A company has 12 employees who hold managerial positions. Of them,
7 are females and 5 are males. The company is planning to send 3 of these 12 managers to a conference. If 3 managers are randomly selected out
of 12,
a) find the probability that all 3 of them are female
b) find the probability that at most 1 of them is a female.
Solution:
Let the selection of a female be called a success and the selection of a male be called a failure.
a) From the given information,
N =total number of managers in the population=12
S = number of successes (females) in the population=7
N - S =number of failures (males) in the population=5
n = number of selections (sample size) =3
x = number of successes (females) in three selections =3 number of failures (males) in three selections =0.
Using the hypergeometric formula, we find
Thus, the probability that all three of the selected managers are female
is 0.1591.
b) The probability that at most one of them is a female is given by the sum of the probabilities that either none or one of the selected managers is a female.
To find the probability that none of the selected managers is a female:
N =12
S =7
N - S =5
n =3
x =0
n - x =3
To find the probability that one of the selected managers is a female:
N =12
S =7
N - S =5
n =3
x =1
n - x =2
In the end,
.
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