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Hydroxides Е(ОН)4 are compounds of nonstoichiometric composition ЕО2.nH2O. Ortho-titanic (a-titanic) H4TiO4 (Ti(OH)4), and more inert meta-titanic(b-titanic) H2TiO3 are known.

Scandium subgroup | Vanadium Subgroup | Scandium and Titanium Subgroups | Vanadium Subgroup | Compounds |


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a-titanic acid can be obtained:

TiCl4 + 4KOH = Ti(OH)4 + KCl

TiCl4 + 2K2CO3 + 2H2O = Ti(OH)4 + 2CO2 + 4KCl

b-titanic acid is formed at:

H4TiO4 = H2TiO3 + H2O

TiCl4 + 2(NH4)2S + 3H2O = H2TiO3 + 4NH4Cl + 2H2S

and high temperature hydrolysis TiCl4:

TiCl4 + H2O = TiOCl2 + HCl

TiOCl2 + H2O = TiO(OH)2 + HCl

Oxo titanium (IV) salts exist in aqueous solutions:

ТіОSO4 + 2NaOH ® ТіО(ОН)2 + Na2SO4

ТіО(ОН)2 + 2HCl ® ТіОCl2 + 2H2O

H4TiO4 and H2TiO3 are very weak acids. Freshly precipitated compounds (a-acid) contain significant content of ОН-groups and more reactive, than aged precipitates (b-acid):

 

 

 

where Ti/ОН\Ti groups are displaced with Ti/О\Ti groups.

Amphoteric a-zirconic acid ZrO2. x H2O (x > 1) can be obtained by the reaction:

ZrCl4 + 4NaOH(cold) = Zr(OH)4¯ + 4NaCl

b-zirconic acid ZrO(OH)2 ­can be prepared:

Zr(OH)4 = ZrO(OH)2 + H2O

ZrCl4 + 4NaOH(hot) = ZrO(OH)2¯ + 4NaCl + H2O

When melting:

ZrO2 + 2KOH = K2ZrO3 + H2O (metazirconates)

ZrO2 + 4KOH = K4ZrO4 + 2H2O (orthozirconates)

Hf(OH)4 can be prepared by the hydrolysis reaction:

HfCl4 + 4NH4OH = Hf(OH)4 + 4NH4Cl

In the series Ti(OH)4—Zr(OH)4—Hf(OH)4 basic properties are strengthened.

Oxosalts are polymers where acid residues are situated between chains –O—Ti—O– as follows:

 

 

 

Oxosalts hydrolyse reversibly in aqeous solutions. Hydrolysis can be suppressed with the addition of an acid:

 

TiOCl2 + 2H2O Û TiO(OH)2 + 2HCl.

Hydrated ions Ti4+, Zr4+, Hf4+ don’t exist due to high charge. Therefore, soluble derivative of them hydrolyses strongly and irreversibly:

ЕСl4 + H2O = ЕOCl2 + 2HCl

Ті(SO4)2 + H2O ® ТіOSO4 + H2SO4.

Titanil and zirconil salts are stable in acid environment, when medium is neutral ortho- (H4ЕO4) and meta- (Н2ЕО3) acids are formed:

TiOSO4 + 2H2O = H2TiO3 + H2SO4

Peroxocompounds [Ti(O2)ОН]+, [Zr(O2)ОН]+ are formed under the action of Н2О2 on solutions containing ТіО2+ / ZrО2+. Peroxocomplex [Ti(O2)ОН]+ is of bright yellow colour. This fact is used in chemical analysis to detect Ti.

COMPOUNDS Ti(III). Oxidation state+3 is distinctive in case of Ti only; compounds of Zr3+, Hf3+ are less stable.

Ti(III) compounds preparation reactions are:

2TiO2 + H2 = Ti2O3 + H2O

2TiCl4 + H2 = 2TiCl3 + 2HCl

оr dissolution of metallic titanium in acids (HCl, diluted H2SO4, and HF):

2Ti + 6HF = 2TiF3 + 3H2

Ti3+ (aq) compounds can usually be synthesized by Ti4+(aq) reduction using hydrogen at the moment of liberation:

2TiOCl2 + Zn + 4HCl = 2TiCl3 + ZnCl2 + 2H2O

TiCl3 readily disproportionates when heated:

2TiCl3 = TiCl2 + TiCl4

Ti2O3 preparation methods are (it has violet colour) as follows:

2TiO2 + C = Ti2O3 + CO

3TiO2 + TiCl4 + 2H2 = 2Ti2O3 + 4HCl

Ті2О3 (tm» 1900°С) does not react with water. When heated /boiling with HNO3:

2Ti2O3 + O2 = 4TiO2

3Ti2O3 + 2HNO3 = 6TiO2 + 2NO + H2O.

The violet colour of Ti(ІІІ) salts aqeous solution is explained by the existence of aquacomplexes [Ti(H2O)6]3+, the presence of d-electron (3d1) in Ti(ІІІ), electron transitions from de to dg-orbitals absorbing quanta of electromagnetic energy.

 

Compounds Ti(II). Corn-coloured TiO can be produced by interaction of free magnesium (or another reductant such as Zn, Ti, C) with TiO2 at high temperature. Compounds Ti(II) are strong reducing agents. For instance, TiO reduces hydrogen at dissolution in H2SO4:

2ТіО + 3H2SO4 ® Ti2(SO4)3 + H2 + 2H2O

Ті(ОН)2 gradually reduces hydrogen of water molecules:

2Ti(OH)2 + 2H2O ® 2Ti(OH)3 + H2

Colourless solution of ТіCl2 quickly becomes brown and then violet (Ті3+) in colour, afterwards the solution again becomes colourless.

Хімічні властивості деяких сполук титану:

 

Хімічні властивості деяких сполук цирконію:

 


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