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Oxidation state +2
Compounds Cu(II). Oxidants usually oxidize copper to Cu+2.
CuO can be obtained by the direct synthesis reaction between simple substances and also by thermal decomposition of many oxygencontaining compounds Cu(II):
(CuOH)2CO3 = 2CuO + H2O + CO2;
2Cu(NO3)2 = 2CuO + 4NO2 + O2.
CuO is a powder of black colour decomposed at tо > 800°С:
4CuO = 2Cu2O + O2
It is reduced readily at 250°С by hydrogen or СО:
CuO + Н2 = Cu + Н2O
Basic properties of CuO are most noticeable. This oxide reacts with strong acids:
CuO + 2HCl = CuCl2 + Н2O
while it interacts also with alkalis when melting:
CuO + 2NaOH = Н2O + Na2CuO2 (cuprates).
Solutions of Cu(ІІ) form blue precipitate of Cu(ОН)2 with alkalis. Cu(ОН)2 can be decomposed easily when heating:
Cu(ОН)2 = CuО + Н2О
Cu(ОН)2 can react with concentrated solutions of alkalis. Deep-blue hydroxocuprates are formed:
Cu(ОН)2 + 2NaOH = Na2[Cu(ОН)4]
Na2[Cu(ОН)4] loses water at 200°С and becomes transformed into oxocuprate Na2CuО2.
Aquaions Cu2+ exist as aquacomplexes [Cu(Н2О)6]2+ that are coloured blue.
The most practically important compound is copper sulfate that can be deposited with crystalline water CuSO4×5H2O (blue vitriol). It loses water after heating and nonaqueous CuSO4 becomes colourless.
Some salts of copper (ІІ) are insoluble in water. The least soluble among them is black CuS that is formed at the action of H2S or soluble sulfides on compounds of Cu(ІІ):
Сu2+ + H2S = CuS + 2H+
Copper carbonate CuСО3 has not been prepared up to the present. Insoluble basic salt appears at the action of carbonates on Cu(ІІ):
2СuSO4 + 2Na2СО3 + H2О = (CuОН)2СО3↓+ 2Na2SO4 + СО2
Crystalline basic carbonates are encountered in nature in the form of beautiful green-coloured mineral malachite (CuОН)2СО3 (or Cu(ОН)2CuCО3) and deep blue azurite 2CuCО3×Cu(ОН)2.
Complexes. Formation of complexes is a quite typical behavior of Сu(ІІ). All coordination compounds are coloured since d-sublevel of Сu2+ is not completed (3d9). Coordination number can be varied: 4 (square planar) or 6 (octahedral).
Nonuniformity of ligands of Cu(II) complexes with coordination number 6 can be shown by the Crystal Field Theory (see scheme below). The least repulsion occurs if unpaired 3d-electron is situated at dx2-y2-orbital that is closest to 4 ligands with negative charge. The appearance of electron pair of dz2-orbital initiates strong repulsion of ligands along z-axis. Therefore, complexes of Cu(II) frequently have space configuration of distorted octahedron. These complexes are shown sometimes in literature as follows: [Cu(H2O)4(H2O)2]2+, [Cu(OH)4(OH)2]4-.
Water molecules of the inner sphere are substituted at the action of NH3 on Cu(II). In this case [Cu(NH3)4(H2O)2]2+ forms of deep blue colour. Cu(NH3)4SO4·H2O compound can be prepared by adding concentrated ammonia solution, NH3, to a saturated aqueous solution of copper sulfate, CuSO4, until all the copper(II) hydroxide that is initially formed redissolves into a clear deep blue solution. The displacement of the fifth water molecule takes place in the concentrated ammonia only. It can be proved by stability constants of complexes (К1=1,4×104, К2=3,2×103, К3=7,8×102, К4=1,4×102 і К5=0,3).
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Free elements | | | Compounds Cu(I). |