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Вариант №1.
l2 |
l1 |
В |
А |
l6 |
l5 |
l4 |
l3 |
А |
В |
Определим распределение мощности на участках схемы:
Проверка:
Р1= +
70= 26,35+43,65 МВт
Проверка:
Р3+ Р4+ Р2= РА-4+ РВ-2
60+70+80=120,28+89,72
210=210
Вариант №2.
А |
В |
l2 |
l3 |
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l7 |
l5 |
l6 |
В |
А |
Проверка:
Р3+ Р4 = РА-4+ РВ-3
60+70=96,27+33,72
130=130
Для тупиковых линий:
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Разработка схем районной электрической сети района. | | | Выбор номинального напряжения. |