Студопедия
Случайная страница | ТОМ-1 | ТОМ-2 | ТОМ-3
АрхитектураБиологияГеографияДругоеИностранные языки
ИнформатикаИсторияКультураЛитератураМатематика
МедицинаМеханикаОбразованиеОхрана трудаПедагогика
ПолитикаПравоПрограммированиеПсихологияРелигия
СоциологияСпортСтроительствоФизикаФилософия
ФинансыХимияЭкологияЭкономикаЭлектроника

Unit 1 and Unit 2 Review Materials

Читайте также:
  1. A BOOK REVIEW
  2. A Content review
  3. A Content review
  4. A Content review
  5. A Content review
  6. A Content review
  7. A Review of the Manager’s Job

Note: The questions on the exam will be based on variations of the following pool of questions and exercises in Unit 1 and Unit 2.

  1. Benchmarks
    1. With regard to computing, define the term benchmark.

Benchmark is tests different computers

    1. What tasks does benchmarking software perform in order to measure the system being tested?

The main task of benchmarking is to testing Processor, Multimedia, Memory, Display Adapter, Hard disk, CD and Network of the computer

    1. How can consumers use benchmarks to help them purchase a computer system?

Benchmarking show user comp characteristics and can made personal rating for comp.

    1. How do benchmarks help identify slow points (bottlenecks) in the system?

After testing computer with Benchmark software, user can see slow points (bottlenecks). At benchmarks analyzed diagram.

 

  1. Binary
    1. Define bit. A Bit is the digit in the Binary number system. (it can have two values, 0 or 1)
    2. Define byte. 1 byte is 8 bit.
    3. Fill in the following chart, listing the prefixes used for the amount of bytes shown:
Amount Prefix
220 mega
230 giga
240 tera
    1. Fill in the following chart, converting binary numbers to decimal and decimal numbers to binary:
      (Note: The numbers that appear in the table below will differ on an exam from the numbers that appear on the exam's review sheet.)
Binary Decimal
   
   
   
   
1 1011  
1111 1100  
11 0011  
1010 0101  
    1. Although in sales literature 1000 bytes and 1024 bytes are both commonly referred to as a kilobyte, in computing the only correct number of bytes in a kilobyte is1024. Explain why 1024 is correct.

Because comp use binary system and 2 in power of 10 is 1024.

    1. How can the difference in measuring bytes presented in part e impact a consumer when they are purchasing a hard disk drive?

Sellers approximate 8 to 10 bits.

2 in power of 40, it is more than 1 terabyte.

  1. Component Identification

Choose among the following components to label the image:

Motherboard
Power supply
BIOS ROM Chip
Cooling fan
Expansion slot
RAM chip
Expansion card
Disk drives
Chipset
IDE cable
Ethernet cable
PCI bus

    1. Label A is Power supply
    2. Label B is Cooling fan
    3. Label C is Expansion slot
    4. Label D is Expansion card
    5. Label E is Motherboard
    6. Label F is Disk drives
    7. Label G is IDE cable

Describe the functionality of each of the following components (in 2 sentences or less):

    1. Microprocessor: incorporates the functions of a computer 's central processing unit (CPU) on a single integrated circuit, or at most a few integrated circuits.
    2. RAM: (random access memory) is a form of computer data storage.
    3. Bus: is a subsystem that transfers data between components inside a computer, or between computers.
    4. Expansion card: in computing is a printed circuit board that can be inserted into an expansion slot of a computer motherboard or backplane to add functionality to a computer system via the expansion bus.
    5. Disk drive: is a device implementing such a storage mechanism with fixed or removable media; with removable media the device is usually distinguished from the media as in compact disc drive and the compact disc.
    6. IDE cable: Integrated Drive Electronics, transfers data to the motherboard from storage devices.
  1. Compression
    1. What is compression?

reduction of the space required for storage(of binary data) by an algorithm which converts the data to a smaller number of bits while preserving the information content.

    1. Describe a benefit of compression.

To reduce the file size.

    1. Describe dictionary-based compression.

Replace common sequence of character with a single codeword,or symbol that points to a dictionary of the original characters, or to the original occurrence of the word.

    1. Describe run-length encoding.

A kind of compression algorithm which replaces sequences ("runs") of consecutive repeated characters (or other units of data) with a single character and the length of the run. This can either be applied to all input characters, including runs

of length one, or a special character can be used to introduce a run-length encoded group. The longer and more frequent the runs are, the greater the compression that will be achieved. This technique is particularly useful for encoding black and

white images where the data units would be single bit pixels.

    1. Describe a benefit of lossy compression.
    2. Name a file type that incorporates lossy compression.

WINZIP

  1. Computer Speed
    1. One Hz is one cycle per second.
    2. Define IPS.

IPS is instructions per second which is a rating of how many instructions can be executed by a processor in a given second.

    1. Answer the following questions on the relationship of Hz to IPS.
      1. Which is a better determiner of speed: MHz or IPS?

IPS is a better determiner of computer performance.

      1. Does a high Hz equal a high IPS, and can they be inversely proportional? Explain.

A high Hz can indicate that the IPS is high, but they are not directly proportional, but can never be inversely proportional

      1. How is it possible for a machine with a lower clock speed (Hz) to have a higher IPS than a machine with a higher clock speed?

An instruction can take a variable amount of cycles or partial cycles. Thus, a computer can execute instructions more quickly than another computer because of this.

    1. What is the relationship between the system clock and Hz?

The system clock sends out pulses at regular intervals to set up the timings for all timed system activities, such as determining the Hz of a processor.

  1. Hexadecimal
    1. Define hexadecimal notation.

Just as decimal numbers can be represented in exponential notation so too can hexadecimal. By convention, the letter p represents times two raised to the power of, whereas e serves a similar purpose in decimal. The number after the p is decimal and represents the binary exponent.

    1. What advantages does hexadecimal have over binary?

Because it will takes more digits to express a value in binary notation than in hexadecimal notation, we have adopted hexadecimal notation as shorthand for binary so that we can express values more concisely.

    1. Which number system, binary or hexadecimal, is used when referencing memory addresses and why?

Hexadecimal,

    1. Fill in the following chart, converting hexadecimal notation to decimal or decimal to hexadecimal notation:
      (Note: The numbers that appear in the table below will differ on an exam from the numbers that appear on the exam's review sheet.)
Decimal Hexadecimal
  F
   
  BF
  EE
   
  6B
  A3
  DD
  1. Images
    1. How are bitmapped images rendered?

Bitmap is composed to a grid of dots, and the color of each dot is stored as a binary number.

    1. How are vectored images rendered?

Vectored images consist of a set of instructions for re-creating a picture. Instead of storing the color value for each pixel, a vector graphic file contains the instructions that the computer needs to create the shape, size, position, and color for each object in an image.

    1. Which image type tends to be more photo-like in quality, bitmapped or vectored?

Bitmap tends to be more photo-like in quality. Since the bitmap is composed of pixels, so is the photo.

    1. Which image type maintains a high image quality, regardless of how it is resized?

Vectored images.

    1. List three image editors.

Powerpoint, photoshop, coreldraw

  1. I/O
    1. Define I/O device.

Stands for input/output device.

    1. Consider that a computer requires I/O devices to be able to interact with its environment. Explain why it is necessary for computers to have these devices.
    2. Give four examples of I/O devices.

Digital camera, printer, speaker, keyboard.

    1. For each I/O device in your answer to part c, explain the device's function from the perspective of a user.

Users take pictures with digital camera. It is stored in digital form, and can be uploaded onto a computer.

The printer can print images or files. Keyboard is used to type data into computer. The speaker is the output device to enable the voice.

  1. Magnetic Media
    1. List two advantages of magnetic media over optical media.

Magnetic disks, with the exception of floppy disks, can be written and read faster than optical disks. Most hard disk drives offer greater capacity than any currently available optical device. And usually the writable of magnetic disks is unlimited.

    1. Fill in the following chart matching the type of media with its storage capacity. The types of media to choose from are Jaz disk, Zip disk, hard disk drive, high-density floppy disk, and double density floppy disk.
Type of Media Storage Capacity
double density floppy disk 720 KB
high-density floppy disk 1.44 MB
Zip disk 100 MB or 250 MB
Jaz disk 1 GB or 2 GB
hard disk drive 20-80 GB
    1. Consider that magnetic media is read by an electromagnet. How does the read/write head discern and transfer data from the magnetic media to the system?

Before data is stored, the particles on the surface of the disk are scattered in random patterns. The disk drives red- write head magnetizes the particles, and orients them in either a positive or negative direction. These patterns of magnetized particles represent 0 and 1 bits.

  1. Moore's Law
    1. Define Moore's Law.

The observation made in 1965 by Gordon Moore, co-founder of Intel, that the number of transistors per square inch on integrated circuits had doubled every year since the integrated circuit was invented. Moore predicted that this trend would continue for the foreseeable future. In subsequent years, the pace slowed down a bit, but data density has doubled approximately every 18 months, and this is the current definition of Moore's Law, which Moore himself has blessed. Most experts, including Moore himself, expect Moore's Law to hold for at least another two decades.

    1. List two extrapolations of Moore's Law that are discussed in the course materials.

Processing power (speed) doubles every 12-18 months. Storage capacity of RAM doubles every 12-18 months.

    1. How can Moore's Law and the extrapolations from Moore's Law assist a consumer in purchasing a computer?

User expect to pay for a computer today that is twice as powerful as the computer that is now 18 months old approximately the same amount of money paid for the old computer.

    1. Define Parkinson's Law of Data.

Parkinson's law of data states that data expands to fill the space available.

    1. Using Parkinson's Law, what projection can be made regarding memory and hard disk usage?
    2. How can Parkinson's Law assist a consumer in purchasing software or components for a computer?
  1. Optical Media
    1. List two advantages of optical media over magnetic media.

Optical media are more durable. They are not ruined by dust or moisture, nor are they vulnerable to electrical damage (however, they can be damaged by physical damages such as scratches). Optical media's MTBF rating (average life expectancy) ranges between 30 and 300 years, while magnetic media utilize magnetic properties that have a MTBF of about 3 or 7 years.

Optical media are less expensive per MB than magnetic disks.

    1. Fill in the following chart. The types of media to choose from are CD-R, CD-RW, CD-ROM, and DVD-ROM.
Type of Media Storage Capacity Number of Times It Can Be Written To
CD-ROM 650-700 MB  
CD-R 650-700 MB Write once
CD-RW 650-700 MB Many
DVD-ROM (SLSS) 4.7 GB Read only
    1. Consider that optical media is read by a laser. How does the laser discern and transfer data from the optical media to the system?

In the optic readable CD-ROM, the data storage consists of millions of indentations burnt into the lacquer coated, light reflecting silver surface. The burnt dents reflect less light than the shiny surface. A weak laser beam is sent to the disk through a two-way mirror and the sensor registers the difference in light reflection from the burnt and shiny areas as zeros and ones.

    1. Consider that a DVD and a CD are the same size. List two reasons a DVD holds more information than a CD.

First, DVDs have narrower tracks, so they can squeeze more tracks onto the same size disk. Both CDs and DVDs are read using light from a laser. But, the CD laser is red, while the DVD laser is blue. Red light has a longer wavelength than a blue light. The blue laser is thus able to produce a smaller beam, allowing it to focus on the tinier tracks of the DVD. The second way that DVDs achieve increased capacity over CDs is by using multiple layers of tracks. The blue laser is not only narrower, but also more powerful. Its beams can penetrate the plastic and focus at different depths.

  1. Picture Quality
    1. Explain resolution, with respect to a monitor.

Signifies the number of dots (pixels) on the entire screen.

    1. List two typical monitor resolutions.

800*600,1024*768

    1. Explain color depth, with respect to a monitor.

The number of distinct colors that can be represented by a piece of hardware or software. Color depth is sometimes referred to as bit depth because it is directly related to the number of bits used for each pixel. A 24-bit video adapter, for example, has a color depth of 2 to the 24th power (about 16.7 million) colors. One would say that its color depth is 24 bits.

    1. List two typical monitor color depths.

24bits,32bits

    1. Consider that the higher the resolution and the higher the color depth, the more system resources are required to display output on the monitor.
      1. Use the resolutions from part b and the color depths from part d to calculate the amount of RAM required to display the image.

1024*768, 32bits RAM = 1024*768*32/8 = 3145728 Bytes,about 3M

      1. Explain the calculation you made in part e.i in a way that confirms the statement made at the beginning of part e —that "the higher the resolution and the higher the color depth, the more system resources are required to display output on the monitor."

From the equation above we know,the capacity of RAM needed to display depends on resolutions and the color depths

  1. Port Identification

Consider the following devices:

Mouse
Printer
Keyboard
Modem
Speaker
Digital camera
Ethernet jack
Monitor

 

 

For the following questions, indicate which device(s) should be plugged in which port(s) A-H shown in the diagram below.

    1. What device(s) can be plugged into port A? Keyboard or mouse.
      1. What is the name of this port?

PS/2 port

      1. Is this a serial port or parallel port?

Serial

    1. What device(s) can be plugged into port B? Digital camera, keyboard, mouse, printer, external storage, network adapter, etc.
      1. What is the name of this port?

USB port

      1. Is this a serial port or parallel port?

Serial

    1. What device(s) can be plugged into port C? Modem or mouse
      1. What is the name of this port?

DB-9 (serial) port

      1. Is this a serial port or parallel port?

Serial

    1. What device(s) can be plugged into port D? Printer
      1. What is the name of this port?

Parallel (printer) port

      1. Is this a serial port or parallel port?

Parallel

    1. What device(s) can be plugged into port E? Speaker
    2. What device(s) can be plugged into port F? Monitor
    3. What device(s) can be plugged into port G? Phone line
    4. What device(s) can be plugged into port H? Ethernet network
  1. RAM
    1. Define RAM.

Random access memory (RAM) is a form of computer data storage. Today, it takes the form of integrated circuits that allow stored data to be accessed in any order with a worst case performance of constant time.

    1. What is the unit of measurement typically used for the speed of RAM?

RAM speed is measured in MHz, PC rating or NS (nanoseconds).

    1. What is SDRAM and how does it work?

SDRAM stands for Synchronous Dynamic Random Access Memory. SDRAM is a type of

semiconductor memory that is used to increase how many instructions your computer's processor

can process in a given amount of time. This is an improvement over the older DRAM or

Dynamic Random Access Memory.

 

You will often hear computer users refer to any RAM, includi SDRAM, when talking about computer speed. Any time you run a program on your computer like a word processing program, game, or Internet browser, your computer's processor loads the executable file (.exe) for that program from the hard drive to the RAM. The larger the program, the larger the amount of RAM it will need to run smoothly. Programs such as Microsoft Office Power Point or state of the art games will take a huge chunk of RAM to run. This means any other programs may slow down or stop completely.

 

If you take a look at your computer right now, you probably have an antivirus program running, your Internet browser, and a few other programs. Each one of those little icons on the bottom of your screen is using RAM.

 

Most newer computers will come with 2 to 4 Gigabytes of SDRAM already installed so you won't have to worry about it at all. If you have an older computer, adding RAM is always a great first step to an upgrade.

 

Most software you can purchase will show you the minimum RAM needed for the software to run efficiently. You should always double-check the packaging of any software to make sure your computer meets or exceeds the recommended amount of RAM.

    1. Data on hard disk drives is accessed indirectly via the file system.
      1. How is data in RAM accessed?
      2. What are the benefits of accessing RAM in this way?
    2. With regard to RAM, what is volatility?

Volatile memory, also known as volatile storage, is computer memory that requires power to maintain the stored information, unlike non-volatile memory which does not require a maintained power supply. It has been less popularly known as temporary memory.

 

Most forms of modern random-access memory (RAM) are volatile storage, including dynamic random-access memory (DRAM) and static random-access memory (SRAM). Content addressable memory and dual-ported RAM are usually implemented using volatile storage. Early volatile storage technologies include delay line memory and Williams tube.


Дата добавления: 2015-11-16; просмотров: 32 | Нарушение авторских прав


<== предыдущая страница | следующая страница ==>
Vocabulary exercises| Unit 1 and Unit 2 Review Materials

mybiblioteka.su - 2015-2024 год. (0.018 сек.)