Given real numbers x, y1, ., y25. In this sequence find two members, the arithmetic mean of which is closest to x.

#include <iostream>

using namespace std;

void main()

{ const int N=25;

float k=0,m,n; float y[N]; cout<<"vvedite znachenia"<<endl;

for (int i = 0; i<N; i++) {cin>>y[i];}

float x=0; cout<<"vvedite znachenia x"<<endl;

cin>>x k=abs(x-(y[0]+y[1])/2);

for(int i=0;i<N;i++)

{for(int j=1;j<N;j++)

{if(k>abs(x-(y[i]+y[j])/2)){k=abs(x-(y[i]+y[j])/2); m=i;n=j; } } }

cout<<"m="<<m<<"n="<<n<<endl;}

23) Given a real number n. Get a real square matrix, where i = 1, n, j = 1, n and

include<iostream.h>

int main()

{int i=1,j=1,n;

double a[100][100],m;

cin>>n;

for(i=1;i<=n;i++)

for(j=1;j<=n;j++)

{m=i+j;m=1/m;a[i][j]=m;}

for(i=1;i<=n;i++)

{for(j=1;j<=n;j++)

cout<<a[i][j]<<" ";cout<<endl;}

system("pause"); return 0;}

Given a real square matrix of order 12. Replace with zeros elements on the diagonal and above it.

#include<iostream.h>

void main()

{ int i,j; int a[100][100];

for(i=0;i<12;i++)

for(j=0;j<12;j++)

a[i][j]=rand()%10;

for(i=0;i<12;i++)

{ for(j=0;j<12;j++)

cout<<a[i][j]<<" "; cout<<endl; }

for(i=0;i<12;i++)

{ for(j=0;j<12;j++)

{ if(j>=i) a[i][j]=0; } }

for(i=0;i<12;i++)

{ for(j=0;j<12;j++) cout<<a[i][j]<<" "; cout<<endl; } system("pause"); }

Given a real square matrix of order mxn. Determine the numbers b1,.., bm, which are equal to the sum of the elements of the corresponding row.

#include<iostream.h>

int main()

{ int i,j,m,n,k=0; int a[100][100],b[100];

cin>>m;

for(i=0;i<m;i++) for(j=0;j<m;j++) a[i][j]=rand()%10;

for(i=0;i<m;i++) { for(j=0;j<m;j++) cout<<a[i][j]<<" "; cout<<endl; }

for(k=0;k<m;k++)

b[k]=0; k=0;

for(i=0;i<m;i++)

{ for(j=0;j<m;j++) { k+=a[i][j]; if(j==m-1)

{ cout<<k<<endl; k=0; } } }

system("pause"); return 0;}

Given a real square matrix of order mxn. Determine the numbers b1,.., bm, which are equal to the product of the elements of the corresponding row.

#include<iostream.h>

int main()

{ int i,j,m,n,k=1;

int a[100][100],b[100];

cin>>m;

for(i=0;i<m;i++)

for(j=0;j<m;j++)

a[i][j]=rand()%10;

for(i=0;i<m;i++)

{ for(j=0;j<m;j++)

cout<<a[i][j]<<" ";

cout<<endl; }

k=1;

for(i=0;i<m;i++)

{ for(j=0;j<m;j++)

{ k*=a[i][j];

if(j==m-1)

{ cout<<k<<endl; k=1; } } }

system("pause");

return 0;}

Дата добавления: 2015-11-16