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For students all specialities



INDIVIDUAL WORK-15

For students all specialities

MODUL 2

 

 

 

Among the given elements has smallest electronegativity:

a

Cesium

b

Fluorine

c

Silicon

d

Sodium

f

Iodine

 

 

0,49 g of hydroxide of twovalent metal reacted with sulfuric acid, as a result was formed 0,8 g of salt. Formula of the hydroxide is:

a

Co(OH)2

b

Mg(OH)2

c

Cu(OH)2

d

Fe(OH)2

f

Ca(OH)2

 

 

In a subgroup of alkaline metals cesium has smallest electronegativity, as it has:

a

Valent electrons comparetively most remote from nucleus

b

Greatest number of valent electrons compared with other elements

c

Greatest atomic mass

d

Greatest number of neutrons in the nucleus

   

 

       

 

 

How many valent electrons has an element if its electronic structure looks like 1 s 22 s 22 p 63 s 23 p 4:

a

 

b

 

c

 

d

 

f

 

 

 

In a highest oxide of an element a ratio between atoms of oxygen and the element makes 1:1. How many valent р -orbitals are filled with electrons in the atom of this element:

a

 

b

 

c

 

d

 

 

 

On a basis of what laws has been made a sequence of elements: carbon, nitrogen, oxygen, fluorine:

a

The elements are located in ascending order of atomic mass

b

Elements of one group

c

All belong to metals

d

All belong to nonmetals

f

Elements of one period

 

 

From the given compounds the formation of hydrogen bonds is possible for:

a

Н2О

b

СН3ОН

c

CF4

d

НІ

f

HCl

 

Find the charge of complex ion, charge, covalency and coordination number of the central atom in potassium tetrahydroxozincate:

a

2–, 2+, 2, 2

b

2+, 2+, 4, 4

c

2–, 2+, 2, 4

d

2–, 2+, 4, 2

f

2–, 2+, 4, 4

 

 

Concentration of ions Cl in 0,01 M solution of the complex compound [Co(NH3)4Cl2]Cl3 (first instability constant is К1 = 4×10–5) is:

a

mol/l

b

mol/l

c

mol/l

d

0,03 mol/l

f

0,01 mol/l

 

 

Enthalpy of methane formation, found by using of the following thermochemical equations

Н2(g)+1/2О2(g) = Н2О(liq); DН = –285,84 kJ

С(solid) + О2(g)= СО2(g); DН = –393,51 kJ

СН4(g) + 2О2(g) = 2Н2О(liq) + СО2(g); DН = –890,31 kJ,

is equal to:

a

–213,5 kJ

b

+159,76 kJ

c

–679,35 kJ

d

–74,88 kJ

f

+56,95 kJ

 

 

For realization of reaction have taken a certain quantity of substances. The reaction ran during 30 minutes, and the measurement of its rate was carried out every 5 minutes. How will be changed the reaction rate during its course:

a

Will pass through a maximum

b

Decrease

c

Will pass through a minimum

d

Will not change

f

Will increase

 

 

In a closed vessel runs homogeneous reaction

2CO + O2 = 2CO2.

The initial concentrations of reactants were equal c(CO) = 0,5 mol/l, c(O2) = 0,2 mol/l. Find equilibrium constant of reaction and equilibrium concentrations of all components, if at some temperature in the reaction had entered 20 % of carbon (ІІ) oxide:

a

Кр= 0,416, [CO] = 0,4 mol/l, [O2] = 0,15 mol/l, [CO2] = 0,1 mol/l

b

Кр= 0,516, [CO] = 0,5 mol/l, [O2] = 0,3 mol/l, [2CO2] = 0,2 mol/l

c

Кр= 0,616, [CO] = 0,6 mol/l, [O2] = 0,4 mol/l, [2CO2] = 0,3 mol/l

d

Кр= 0,316, [CO] = 0,3 mol/l, [O2] = 0,2 mol/l, [2CO2] = 0,15 mol/l

f

Кр= 0,208, [CO] = 0,2 mol/l, [O2] = 0,075 mol/l, [2CO2] = 0,05 mol/l

 


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