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Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
Sin2A+Cos2A=1 TgACtgA=1 TgACosA=SinA TgASinA=CosA | Cos(A±B)=CosACosB∓SinASinB Sin(A±B)=SinACosB±CosASinB Tg(A±B)=(TgA±TgB)/(1∓TgATgB) Ctg(A±B)=(1∓CtgACtgB)/(CtgA±CtgB) | |||||||||
SinASinB=(1/2)(Cos(A-B)-Cos(A+B)) CosACosB=(1/2)(Cos(A-B)+Cos(A+B)) SinACosB=(1/2)(Sin(A-B)+Sin(A+B)) | Sin2(A/2)=(1-CosA)/2 Cos2(A/2)=(1+CosA)/2 Tg(A/2)=(1-CosA)/SinA =SinA/(1+CosA) Ctg(A/2)=(Tg(A/2))-1 | |||||||||
Sin2A=2SinACosA Cos2A=Cos2A-Sin2A=2Cos2A-1=1-2Sin2A=(CtgA-TgA)/(CtgA+TgA) Tg2A=2TgA/(1-Tg2A)=2CtgA/(Ctg2A-1)=2/(CtgA-TgA) Ctg2A=(Ctg2A-1)/2CtgA=(CtgA-TgA)/2 | Sin2A*Cos2A=(1/8)(1-Cos4A) Sin3A*Cos3A=(1/32)(1-Cos4A) | |||||||||
Sin3A=3SinA-4Sin3A Cos3A=4Cos3A-3CosA Tg3A=(3TgA-Tg3A)/(1-3Tg2A) Ctg3A=(3CtgA-Ctg3A)/(1-3Ctg2A) | SinA+SinB=2Sin((A+B)/2)Cos((A-B)/2) SinA-SinB=2Sin((A-B)/2)Cos((A+B)/2) CosA+CosB=2Cos((A+B)/2)Cos((A-B)/2) CosA-CosB=-2Sin((A-B)/2)Sin((A+B)/2) | |||||||||
1+Tg2A=1/Cos2A 1+Ctg2A=1/Sin2A 1+Tg2A=1/Cos2A | Sin2A=(1-Cos2A)/2 Cos2A=(1+Cos2A)/2 Tg2A=(1-Cos2A)/(1+Cos2A) Ctg2A=(1+Cos2A)/(1-Cos2A) | Sin3A=(3SinA-Sin3A)/4 Cos3A=(3CosA+Cos3A)/4 | ||||||||
x=(-1)nAsinX+πn SinX=0 x=πn; SinX=1 x=(π/2)+2πn; SinX=-1 x=-(π/2)+2πn x=±AcosX+2πk CosX=0 x=(π/2)+πn; CosX=1 x=2πn; CosX=-1 x=π+2πn x=AtgX+πn | ||||||||||
Sin | Cos | Tg | Ctg | alog(a)b=b logaa=1 a>0;a≠1 loga1=0 a>0;a≠1 loga(bc)=logab+logac loga(b/c)=logab-logac logabp=plogab loga^kb=(1/k)logab logab=1/logba logab=logcb/logca logaan=n logab*logbc=logac | ↑ Sin(1/2, √2/2, √3/2)(++--), →Cos(1/2, √2/2, √3/2)(-+-+), ↑ Tg(1/√3, 1, √3)(-++-), →Ctg(1/√3, 1, √3)(-++-) | |||||
(π/2)-A | Cos | Sin | Ctg | Tg | ||||||
(π/2)+A | Cos | -Sin | -Ctg | -Tg | ||||||
π-A | Sin | -Cos | -Tg | -Ctg | ||||||
π+A | -Sin | -Cos | Tg | Ctg | ||||||
(3π/2)-A | -Cos | -Sin | Ctg | Tg | ||||||
(3π/2)-A | -Cos | Sin | -Ctg | -Tg | ||||||
2π-A | -Sin | Cos | -Tg | -Ctg | ||||||
2π+A | Sin | Cos | Tg | Ctg | ||||||
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