|
INDIVIDUAL WORK-14
For students all specialities
MODUL 2
The number of elements in the period is determined by: | |
a | Valency of elements |
b | Number of filled up atomic orbitals |
c | Orbital quantum number |
d | Number of energy levels |
f | Structure of an external quantum level |
Among the given elements the greatest value of energy of an electron affinity has: | |
a | Carbon |
b | Aluminium |
c | Sulfur |
d | Oxygen |
f | Fluorine |
Among the given elements electron jump up is most characteristic for: | |
a | Chromium |
b | Calcium |
c | Plumbum |
d | Copper |
f | Scandium |
Among the given ions a similar to ion Na+ electronic shell is: | |
a | Ca2+ |
b | Mg2+ |
c | H+ |
d | K+ |
f | Li+ |
Bromine has larger oxidizing properties, than iodine, because: | |
a | Radius of atom of bromine is greater, than radius of atom of an iodine |
b | Oxidizing properties of iodine is greater, than oxidizing properties of bromine |
c | Radius of atom of iodine is greater, than radius of atom of bromine |
d | Electron affinity of atom of bromine is greater, than electron affinity of atom of iodine |
f | Electron affinity of atom of iodine is greater, than electron affinity of atom of bromine |
At the decomposition of 25 g of a carbonate of twovalent metal was liberated 5,6 l carbon dioxide under normal conditions. The formula of the salt looks like: | |
a | SrCO3 |
b | CaCO3 |
c | MgCO3 |
d | BeCO3 |
f | BaCO3 |
Molecular orbitals are bonding if: | |
a | Density of electronic clouds of atoms, which form a molecule, are more then density of an electronic cloud of molecular wave function |
b | Density of an electronic cloud in internuclear space is increased |
c | Density of an electronic cloud in internuclear space decreases |
d | Density of an electronic cloud in internuclear space does not change |
Find the charge of a complex ion, charge, covalency and coordination number of the central atom in a hexaammine chromium (ІІІ) chloride, and also sum of coefficients in the equation of reaction of exchange of this salt solution with silver nitrate solution: | |
a | 2+, 2+, 6, 6, 7 |
b | 3+, 3+, 6, 6, 4 |
c | 2+, 2+, 6, 6, 8 |
d | 3+, 3+, 6, 6, 8 |
f | 3+, 3+, 5, 5, 8 |
Find concentration of molecules NH3 which are formed according the first step of dissociation (first instability constant is К1 = 4×10–5) in 0,01 M solution of hexaamminecobalt (ІІІ) chloride, if concentration of the complex ion [Co(NH3)6]3+ at its dissociation practically does not change: | |
a | mol/l |
b | mol/l |
c | 0,01 mol/l |
d | mol/l |
f | 4×10–5×0,01 mol/l |
Value for the reaction H2(g)+ I2(g) = 2HI(g), if react= –114,12 kJ/mol; react= 21,54 J/mol×К, is equal to: | |
a | –115,09 kJ/mol |
b | –120,54 kJ/mol |
c | –118,29 kJ/mol |
d | –116,33 kJ/mol |
f | –113,75 kJ/mol |
A reaction runs according the equation А2 + В2 = 2АВ. The initial concentration of substance A is equal 0,8 mol/l, and substance B is 1mol/l. After some time the concentration of substance A has been decreased down to 0,5 mol/l. Find thus the concentration of substance В: | |
a | 0,75 mol/l |
b | 0,3 mol/l |
c | 0,5 mol/l |
d | 0,2 mol/l |
f | 0,7 mol/l |
The equilibrium constant of homogeneous reaction 2Н2S + 3O2=2Н2O + 2SO2 is equal 1. The equilibrium concentrations were: [H2S] =2 mol/l; [O2] = 4 mol/l; [H2O] = 4 mol/l. Find the equilibrium concentration of sulfur oxide: | |
a | 2 mol/l |
b | 6 mol/l |
c | 4 mol/l |
d | 3 mol/l |
f | 5 mol/l |
Дата добавления: 2015-11-05; просмотров: 13 | Нарушение авторских прав
<== предыдущая лекция | | | следующая лекция ==> |
For students all specialities | | | For students all specialities |